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Post by antigua on Feb 20, 2017 21:07:39 GMT -5
There was a discussion about neodymium saturating steel cores to the point of lowering inductance over on the TDPRI forum; and since this is a good investigation into the working of pickups, I'm reposting my contribution here, lest it get lost in the ether at TDPRI... ~~*~~*~*~*~ The pickup with steel six cores shows 3.961H @ 120Hz: With six neodymium bottons over the slugs the inductance showed 3.960 when I took the picture, but this number bounces around by +/-3 mH as I jiggle the wires, so the inductance is effectively the same, and so they must not be saturating the core. But then I stuck a giant neodymium over the pickup, one that has many more times the flux density of the buttons, and the inductance drops to 3.269 henries, so it does appear that the larger neos saturate the core somewhat: Note that with no steel cores at all, the inductance drops below 2 henries, as this is a typical Strat pickup with about 6k ohms worth of windings. At 3.269 henries, this pickups still has far more inductance than one with air cores, or even one with AlNiCo cores, so the core is not saturated to the extent that it performs like air. I do not know whether this means there is only partial saturation, or if a partial loss of inductance is to be expected (relative to air core) when a core reaches complete saturation.
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Post by ms on Feb 21, 2017 6:54:13 GMT -5
It looks as though you have applied enough H so that the magnetization has moved some along the hysteresis curve in the direction of saturation. That is, the change is B you are getting is not as large for the same applied change in H as it was with smaller magnets. I thing there is still a considerable way to go before reaching complete saturation.
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Post by antigua on Feb 22, 2017 0:41:17 GMT -5
The magnet is only directly above a few of the pole pieces, I wonder if perhaps the steel that is mostly directly below the neo's is saturdated, while the steel that is further away isn't. I'll have to mess with this some more.
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