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Post by firebottles on Apr 26, 2009 10:10:12 GMT -5
OKay.. recording my band.. I wish to use a poweramp to drive a box with A stereo input and 6 stereo headphone jacks out each with their own volume control.
So all I need to do is build the manifold and not the amp.
Does it work like that? or
does each channel have to have its own little amp because of speaker resistance issues?
Perhaps that is why a headphone distribution unit is more expensive than it should seem.
Thoughts?
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Post by firebottles on Apr 26, 2009 10:16:16 GMT -5
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Post by JohnH on Apr 26, 2009 15:45:17 GMT -5
My thought is to ask if all members are happy to get the same volume level, and use headphones of the same sensitivity?
John
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Post by sumgai on Apr 27, 2009 1:23:18 GMT -5
bottles, That diagram can be repeated as often as you wish, the resistor values are not magical for having just the four outputs. John's correct to point out that a single resistor value will cause different volume levels in differing headphones. Inserting a low-value (on the order of 100Ω or less) pot in place of the 18Ω resistor (errr, a dual-ganged pot will be necessary here, we are dealing with stereo) will allow each band member to use his/her favorite 'phones. Just make sure that you connect the "hot" lines to the outer terminal, and the phone jacks to the wiper(center) terminal of each pot.  Other than that, things are pretty simple. You're correct too, in that a lot of simple devices like this are priced as if they were made of gold. Sad, just plain sad.  HTH sumgai |
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Post by firebottles on Apr 27, 2009 8:59:04 GMT -5
Thanks guys.. that helps alot!
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