Short answer is no, there's no direct correspondence like that. This is a complex system of inductance, capacitance, and resistance and everything interacts with everything else, so it's tough to make generalizations, but...
In general ( ), a resistor parallel to the pickup will reduce the resonant peak at the cutoff frequency while a capacitor will tend to lower the actual cutoff frequency itself.
A standard tone control actually kind of does both. For half or so of the rotation down from 10, it's the resistance working against the inductance of the pickup that darkens the tone. Toward the bottom, the cap starts to do its thing, part of which is to actually stop the LR filter cutoff from going toward 0 and killing the whole signal.
If you're interested in these things, take a look in our Reference section at JohnH's GuitarFreak spreadsheet app, and if you want to get super geeky, check out the new subforum of the Pickups section which is all about analysis of various pickups and their interactions with each other and the rest of the circuit.
Last Edit: Oct 27, 2016 19:29:18 GMT -5 by ashcatlt