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Post by frets on Dec 6, 2023 16:35:36 GMT -5
Hi Guys, 😸 I have shown my drop in Les Paul boards but wanted to show my recently developed Strat boards. They are very similar to Obsidian Wire drop ins but I’m using a mixture of CTS and Bourns Push Pulls. They only use CTS. I still haven’t figured out how Obsidian wires the CTS push pulls with no wires. But on mine, I have to use wires from the push pull to the board. The push pull face board does most of the wiring but there inevitably are a few connections that have to be made to the main board. Here is a Strat PTB.  And here is a Volume pot for an HSS harness (Neck On Pull up). You can see I used two wires to connect the pot to the main board.  I have a few of boards developed from what guys ask for. The main board costs about $2 from JCL - China. The push pull face boards are around 33 cents a piece. The Wago terminal is the expensive part at anywhere from $2.50 to $4.00 depending upon the number of slots. Overall, the boards have reduced my wiring time in half and I am assured that the wiring is correct every time. I have I think 5 Strat models and am planning more. I know this has been done before, I just wanted to share them. I guess it is kind of showing off. But I thought you all would enjoy seeing them. At least it gives us something to talk about. I guess for some, it takes the pleasure out of actually hard wiring a harness. For me, it is a huge time saver and also quality control. |
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Post by newey on Dec 6, 2023 20:00:20 GMT -5
Oh, but the Tone Nazis will say that it can't have the elusive mystery mojo because it doesn't have vintage-aged pushback cloth insulated wires . . .  . Seriously, I think it's a great idea, as you note it's been done, but if you can hit a price point that others can't, you could do well. Others have also used a bunch of DIP switches on their boards to allow for switching to different options (hint, hint  ), but that's only really viable for rear-cavity guitars. |
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Post by frets on Dec 7, 2023 16:58:03 GMT -5
Newey,
I have thought about adding switching to the Les Paul boards. I will probably do it in the future. Probably just cap value switching using hexidecimals and small polypropylenes. Or, just dip switches to change the cap values on both the bridge and neck tone. But I’m open to any ideas for switching that anyone might have. I did try a Jimmy Page Les Paul but the push pulls interfered with getting the pickup wires into the terminal.
I do plan on selling them individually at a price point significantly less than Obsidian Wire.
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Post by mikecg on Dec 7, 2023 18:58:57 GMT -5
Nice looking soldered joints - someone knows how to solder!
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Post by unreg on Dec 9, 2023 22:56:08 GMT -5
It does seem like a great idea! Cutting wiring time in HALF is really cool for your business! frets, what are hexidecimals? I know hexadecimal is a base 16 numbering system that’s used digitally bc it allows larger numbers with fewer characters (i.e. $FF == 255; here, 2 characters of hexadecimal is equal to 3 characters of decimal). And obviously hexadecimal is just a representation of our base 10 decimal numbers. Are you saying that someone decided to create a product and presented its measurements in hexadecimal format AND then decided to call it a hexidecimal?  That’s like creating a ruler and naming it a millimeter. Or maybe hexidecimal is just a slang term. I’m sorry, I don’t know. |
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Post by frets on Dec 10, 2023 12:03:55 GMT -5
Unreg, Here is a hexidecimal switch.  It provides 16 positions in a rotary format. When wired with 4 capacitors in a specific way, it can generate bypass plus 15 different uF levels in ascending order. |
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Post by unreg on Dec 11, 2023 0:02:42 GMT -5
Ahhh! That’s really cool! Thank you for replying frets. So a hexidecimal IS related to the base 16 numbering system hexadecimal! Base 16 means it has 16 digits… 0 - 9, 10 digits, and A - F, 6 more digits. A is 10, B is 11, C is 12, D is 13, E is 14, and F is 15. That F or 15 being the highest digit works just like our base 10 system, where 9 is the highest digit. The 0 adds the crucial extra digit. So, you get 16 digits in base 16 AND 10 digits in base 10. Heh, I’ll be quiet now; this isn’t an all computer programming crowd. p.s. Any base greater than 1 is possible. Binary is base 2, it has 0 and 1; Octal is base 8, it has 0 - 7; you just have to have enough different characters for digits for a base greater than 16. |
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Post by reTrEaD on Dec 11, 2023 0:36:05 GMT -5
Base 16 means it has 16 digits Base 16 means each digit has 16 possible states. Please google "what is a digit?", then post your new understanding of what a digit means in mathematics. |
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Post by reTrEaD on Dec 11, 2023 0:48:48 GMT -5
Here is a hexidecimal switch. *image snipped for brevity* It provides 16 positions in a rotary format. When wired with 4 capacitors in a specific way, it can generate bypass plus 15 different uF levels in ascending order. Right. And to elaborate the point, we could refer to it as a Binary Coded Hexadecimal switch. The input (rotor) has 16 different positions and the output is 4-bit binary. |
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Post by unreg on Dec 11, 2023 1:25:03 GMT -5
Base 16 means it has 16 digits Base 16 means each digit has 16 possible states. Ah, I missed the adjective separate when describing the base digits. It’s not difficult to understand what I meant; I understand you ARE against me. I’m not against you, sir reTrEaD. Merry Christmas!  |
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Post by reTrEaD on Dec 12, 2023 8:33:25 GMT -5
It’s not difficult to understand what I meant More importantly, it IS very easy for someone who is unsure of what a digit is, to 'learn' a completely incorrect understanding, from what you said. I understand you ARE against me. A declaration of victimhood? Let's examine that to determine if there's any factual basis. - I AM against falsehoods masquerading as facts. - I AM against impromptu 'lessons' that contain blatant inaccuracies. - While we all make mistakes, I AM against lame excuses being offered when a simple 'mea culpa' would be more appropriate. - I AM against those who aspire to teach, but are unwilling to learn. If you engage in any of those activities, you ARE likely to find yourself at odds with me. I'm not always against snarkiness, there is a time and place for it. There are times in jovial exchanges when snark can be amusing However, after claiming victimhood, embedding snark is not a good look. I recommend careful consideration of where and when to employ it. Else you may find yourself a victim of your own indiscretion. |
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Post by Guitar-Freak on Feb 16, 2024 10:26:33 GMT -5
Unreg, Here is a hexidecimal switch. It provides 16 positions in a rotary format. When wired with 4 capacitors in a specific way, it can generate bypass plus 15 different uF levels in ascending order. When you say if wires in a certain way, which way is that? |
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Post by asmith on Feb 16, 2024 11:14:07 GMT -5
Oh, no way, I was thinking about starting to do this myself. Of course others are already doing it!
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Post by Guitar-Freak on Feb 18, 2024 5:00:12 GMT -5
Unreg, Here is a hexidecimal switch. It provides 16 positions in a rotary format. When wired with 4 capacitors in a specific way, it can generate bypass plus 15 different uF levels in ascending order. When you say if wires in a certain way, which way is that? Since Frets (Matthew?) couldn’t or wouldn’t, here’s the answer for anyone else wondering or not really caring enough to figure it out: To achieve bypass plus 15 different uF levels in ascending order using a hexadecimal switch and 4 capacitors, you can wire them in a binary-weighted configuration. Here's how you can wire them: 1. Start by connecting one end of each capacitor to the common terminal of the switch. 2. Connect the other end of each capacitor to a different switch position, ensuring that each position corresponds to a different binary value. 3. The capacitors should be connected in such a way that each position doubles the capacitance of the previous one. For example, if you have capacitors with values of 1uF, 2uF, 4uF, and 8uF: - Position 0 (Bypass): All capacitors disconnected. - Position 1: Connect the 1uF capacitor. - Position 2: Connect the 2uF capacitor. - Position 3: Connect both the 1uF and 2uF capacitors in parallel for a total of 3uF. - Position 4: Connect the 4uF capacitor. - Position 5: Connect the 1uF and 4uF capacitors in parallel for a total of 5uF. - Position 6: Connect the 2uF and 4uF capacitors in parallel for a total of 6uF. - Position 7: Connect the 1uF, 2uF, and 4uF capacitors in parallel for a total of 7uF. - Position 8: Connect the 8uF capacitor. - Position 9: Connect the 1uF and 8uF capacitors in parallel for a total of 9uF. - Position A: Connect the 2uF and 8uF capacitors in parallel for a total of 10uF. - Position B: Connect the 1uF, 2uF, and 8uF capacitors in parallel for a total of 11uF. - Position C: Connect the 4uF and 8uF capacitors in parallel for a total of 12uF. - Position D: Connect the 1uF, 4uF, and 8uF capacitors in parallel for a total of 13uF. - Position E: Connect the 2uF, 4uF, and 8uF capacitors in parallel for a total of 14uF. - Position F: Connect all capacitors (1uF + 2uF + 4uF + 8uF) in parallel for a total of 15uF. 👍 |
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Post by reTrEaD on Feb 18, 2024 10:59:54 GMT -5
frets = Cindi To achieve bypass plus 15 different uF levels in ascending order using a hexadecimal switch and 4 capacitors, you can wire them in a binary-weighted configuration. Here's how you can wire them: 1. Start by connecting one end of each capacitor to the common terminal of the switch.2. Connect the other end of each capacitor to a different switch position, ensuring that each position corresponds to a different binary value. 3. The capacitors should be connected in such a way that each position doubles the capacitance of the previous one. I reckon you should reconsider step 1.
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Post by frets on Feb 18, 2024 13:44:32 GMT -5
To be clear, Matthew is my Unclr who owns the business. I work for him.
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), but that's only really viable for rear-cavity guitars.
That’s like creating a ruler and naming it a millimeter. 
